2[k-(2k+18)+16]=2(k+2)

Solution for 2[k-(2k+18)+16]=2(k+2) equation:

Simplifying
2[k + -1(2k + 18) + 16] = 2(k + 2)

Reorder the terms:
2[k + -1(18 + 2k) + 16] = 2(k + 2)
2[k + (18 * -1 + 2k * -1) + 16] = 2(k + 2)
2[k + (-18 + -2k) + 16] = 2(k + 2)

Reorder the terms:
2[-18 + 16 + k + -2k] = 2(k + 2)

Combine like terms: -18 + 16 = -2
2[-2 + k + -2k] = 2(k + 2)

Combine like terms: k + -2k = -1k
2[-2 + -1k] = 2(k + 2)
[-2 * 2 + -1k * 2] = 2(k + 2)
[-4 + -2k] = 2(k + 2)

Reorder the terms:
-4 + -2k = 2(2 + k)
-4 + -2k = (2 * 2 + k * 2)
-4 + -2k = (4 + 2k)

Solving
-4 + -2k = 4 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-4 + -2k + -2k = 4 + 2k + -2k

Combine like terms: -2k + -2k = -4k
-4 + -4k = 4 + 2k + -2k

Combine like terms: 2k + -2k = 0
-4 + -4k = 4 + 0
-4 + -4k = 4

Add '4' to each side of the equation.
-4 + 4 + -4k = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -4k = 4 + 4
-4k = 4 + 4

Combine like terms: 4 + 4 = 8
-4k = 8

Divide each side by '-4'.
k = -2

Simplifying
k = -2